# Section 4C

### Savings Plans and Investments

...

#### Generalities

Last time we were discussing investments.

It is good when one has a decent principal to invest. After that one can do nothing but calculate how much it will be after so many years. However, most people miss this opportunity. They also want to accumulate an amount of money, and the strategy is: invest with small portions, put aside some amounts regularly. That is how Individual Retirement Accounts (IRA), 401(k), and 529 plans for education work. Today we consider these strategies in some details.

#### Savings plans: the idea.

Suppose you deposit $$\ 100$$ monthly into a bank with
an APR of $$12\%$$ ( $$1 \%$$ per month)

At the end of the first month you have $$\ 100$$on the account.

At the end of the second month you deposit another $$\ 100$$.

But they have already kept your $$\ 100$$ during a month, so you earn $$1 \%$$ of this sum, which is $$\ 1$$.

All together, at the end of the second month you have
$$\ 100$$ which you have brought them last time, $$\ 1$$ of interest, and another $$\ 100$$ which you have just brought them now.

That is
$$\ 100 + \ 1 + \ 100 = \ 201$$

#### Savings plans: the idea ... continued

At the end of third month:
$$201 + 1\% \times 201 + 100 = \ 303.01$$
At the end of the 4-th month:
$$301.01 + 1\% \times 301.01 +100 = \ 406.04$$
At the end of the 5-th month:
$$406.04 +1\% \times 406.04 +100= \ 510.10$$
At the end of the 6-th month:
$$510.10 +1\% \times 510.10 +100=\ 615.20$$
and so on ...

It is correct but quite awkward to calculate this way

Instead we will use Saving Plan Formula which encodes these calculations.

#### Savings Plan Formula (regular payments)

$$A = PMT \times \frac{ \left[ \left( 1 + \frac{APR}{n} \right)^{(nY)} -1 \right] }{\left( \frac{APR}{n} \right)}$$

where

$$A$$ = accumulated savings plan balance (FV -- future value)

$$PMT$$ = regular payment (deposit) amount

$$APR$$ = annual percentage rate (in decimal)

$$n$$ = number of payment periods per year

$$Y$$ = number of years

#### Savings Plan Formula (regular payments)

$$A = PMT \times \frac{ \left[ \left( 1 + \frac{APR}{n} \right)^{(nY)} -1 \right] }{\left( \frac{APR}{n} \right)}$$

In the example we started with:

$$PMT= \ 100$$, $$APR = 12 \%$$, $$n=12$$ for monthly payments

After 6 months ( $$Y=0.5$$ ):

$$A = 100 \times \frac{ \left[ \left( 1 + \frac{0.12}{12} \right)^{(12 \times 0.5)} -1 \right] }{\left( \frac{0.12}{12} \right)} = \ 615.20$$
as we already calculated, while after 5 years ( $$Y=5$$ ):

$$A = 100 \times \frac{ \left[ \left( 1 + \frac{0.12}{12} \right)^{(12 \times 5)} -1 \right] }{\left( \frac{0.12}{12} \right)} = \ 8166.97$$

#### Savings Plan Formula (regular payments)

$$A = PMT \times \frac{ \left[ \left( 1 + \frac{APR}{n} \right)^{(nY)} -1 \right] }{\left( \frac{APR}{n} \right)}$$

Assume that you know the final accumulated balance you need. What should be your regular payment to get there after a certain amount of time?

Savings Plan Formula solved for payments:
$$PMT= A \times \frac {\left( \frac{APR}{n} \right)} { \left[ \left( 1 + \frac{APR}{n} \right)^{(nY)} -1 \right] }$$

#### Savings Plan Formula solved for payments

$$PMT= A \times \frac {\left( \frac{APR}{n} \right)} { \left[ \left( 1 + \frac{APR}{n} \right)^{(nY)} -1 \right] }$$

In our example, $$PMT= \ 100$$, $$APR = 12 \%$$, $$n=12$$ for monthly payments, an amount of $$\ 8,166.97$$ has been accumulated within a period of 5 years.

Assume that we want to accumulate $$\ 10,000$$ under the same conditions within the same period of time. Then instead of $$\ 100$$, the monthly deposit should be
$$PMT= 10000 \times \frac {\left( \frac{0.12}{12} \right)} { \left[ \left( 1 + \frac{0.12}{12} \right)^{(12 \times 5)} -1 \right] } = \ 122.44$$

## Characteristics of an investment

There are various investments.

Clearly, the bigger is the APY, the better an investment looks.

However, in real life, the APR is not constant; it floats. So does APY.

We thus need other quantitative characteristics of investments.

#### Characteristics of an investment: total return

Assume that you deposit $$\ 1,000$$, and accumulate $$\ 1,500$$ after 5 years. How good was the investment?

The amount grew up by $$\frac{1500-1000}{1000} = 0.5 = 50\%$$

In general, total return is the percentage change in the investment value:

$$\text{total return} = \frac{A-P}{P} \times 100 \%$$

where A is accumulated balance, and P is the starting principal.

#### Characteristics of an investment: annual return

Another person has got same $$\ 1,500$$ but after 10 years instead of 5 years

While the total return is the same $$50 \%$$, the quality of these two investments is clearly different.

Probably, the APR was different: yours was higher.

But we cannot compare the two APR's directly, because

in real life, APR is not constant, it is floating with time

#### Characteristics of an investment: annual return

The annual return is the APY that would give the same overall growth It is calculated by the formula
$$\text{annual return} = \left( \frac{A}{P} \right) ^{(1/Y)} -1$$

where A is accumulated balance, P is the starting principal, and Y is the number of years.

In the examples, when $$A=\1,500$$ comes out $$P=\ 1,000$$ within 5 years,

$$\text{annual return} = \left( \frac{1500}{1000} \right) ^{(1/5)} -1 =0.084 = 8.4 \%$$

while for the same growth within 10 years,

$$\text{annual return} = \left( \frac{1500}{1000} \right) ^{(1/10)} -1 =0.041 = 4.1 \%$$

#### Summary

Today we considered Savings plan formula

$$A = PMT \times \frac{ \left[ \left( 1 + \frac{APR}{n} \right)^{(nY)} -1 \right] }{\left( \frac{APR}{n} \right)}$$

Savings Plan Formula solved for payments
$$PMT= A \times \frac {\left( \frac{APR}{n} \right)} { \left[ \left( 1 + \frac{APR}{n} \right)^{(nY)} -1 \right] }$$

Characteristics of an investment:

$$\text{total return} = \frac{A-P}{P} \times 100 \%$$

$$\text{annual return} = \left( \frac{A}{P} \right) ^{(1/Y)} -1$$